Assuming μ = 0 ( frictionless surface), we get: F cos 30° = ma
Potential energy (PE) = mgh = 0.5(10)(10) = 50 J Assuming μ = 0 ( frictionless surface), we
Here are some sample mechanics problems with solutions: 2 )mv² = (&frasl
Kinetic energy (KE) = (⁄ 2 )mv² = (⁄ 2 )(0.5)(14.14)² = 50 J Assuming μ = 0 ( frictionless surface), we
Using the equation: F cos θ = μN, where μ is the coefficient of friction and N is the normal force.
Using the equation: s = v₀t + (⁄ 2 )at², we get: s = 10(5) + (⁄ 2 )(2)(5)² = 50 + 25 = 75 m