Eli’s pencil moves: ( 27^{-2/3} = \frac{1}{(\sqrt[3]{27})^2} = \frac{1}{3^2} = \frac{1}{9} ). “It works.”
Eli stares at his homework: ( 16^{3/2} ), ( 27^{-2/3} ), ( \left(\frac{1}{4}\right)^{-1.5} ). His notes read: “Fractional exponents: numerator = power, denominator = root.” But it feels like memorizing spells without understanding the magic. Fractional Exponents Revisited Common Core Algebra Ii
“Last boss,” Ms. Vega taps the page: ( \left(\frac{1}{4}\right)^{-1.5} ). “Last boss,” Ms
Ms. Vega sums up: “Fractional exponents aren’t arbitrary. They extend the definition of exponents from ‘repeated multiplication’ (whole numbers) to roots and reciprocals. That’s the — rewriting expressions with rational exponents as radicals and vice versa, using properties of exponents consistently.” Vega sums up: “Fractional exponents aren’t arbitrary
Ms. Vega pushes her mug aside. “You’re thinking like a robot. Let’s tell a story.”
“I get ( x^{1/2} ) is square root,” Eli sighs, “but ( 16^{3/2} )? Do I square first, then cube root? Or cube root, then square?”
“Rewrite ( 1.5 ) as ( \frac{3}{2} ).” Ms. Vega leans in. “The rule holds for all rational exponents. Now: The base is ( \frac{1}{4} ). Negative exponent → flip it: ( 4^{3/2} ). Denominator 2 → square root of 4 is 2. Numerator 3 → cube 2 to get 8. Done.”