\[A = rac{πd^2}{4} = rac{π(20)^2}{4} = 314.16 mm^2\] The stress in the rod is given by:
\[σ = rac{P}{A} = rac{10,000}{314.16} = 31.83 MPa\] Assuming a modulus of elasticity of 200 GPa, the strain in the rod is given by: Beer Mechanics Of Materials 6th Edition Solutions Chapter 3
Mechanics of Materials 6th Edition Solutions Chapter 3: Understanding the Fundamentals of Material Properties** \[A = rac{πd^2}{4} = rac{π(20)^2}{4} = 314